The diameter of gardern roller is 1.4 meter and it is 2 meter long . How much area will it cover in 50 revolutions ?
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3
Diameter = 1.4 m
Radius = 0.7 m
Length = 2 m
Area in 1 revolution = CSA of the cylinder.
2πrh = 2 x 22/7 x 0.7 x 2 = 8.8 m²
Area covered in 50 revolutions = 50 x 8.8 = 440 m²
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Radius = 0.7 m
Length = 2 m
Area in 1 revolution = CSA of the cylinder.
2πrh = 2 x 22/7 x 0.7 x 2 = 8.8 m²
Area covered in 50 revolutions = 50 x 8.8 = 440 m²
Hope This Helps You!
Anku123456789:
Thx sister
it is 440 sq m
plz check , Bella
Answered by
2
roller is in the shape of cylinder
diameter = d= 1.4m
radius = r = d/2 = 1.4/2 = 0.7m
height of the roller = length of the roller = h= 2 m
area covered with the roller for one revolution = CSA of the the roller
area covered in 50 revolutions = 50 * CSA of the cylinder
= 50 *(2πrh)
=50 * 2*22/7 * 0.7 * 2 m²
=(50*2*22*7*2)/(7*10)
after cancellation
= 440m²
diameter = d= 1.4m
radius = r = d/2 = 1.4/2 = 0.7m
height of the roller = length of the roller = h= 2 m
area covered with the roller for one revolution = CSA of the the roller
area covered in 50 revolutions = 50 * CSA of the cylinder
= 50 *(2πrh)
=50 * 2*22/7 * 0.7 * 2 m²
=(50*2*22*7*2)/(7*10)
after cancellation
= 440m²
i did the mistake , it is 440 sq m
in the denominator we have already 7 and 10 comes from 0.7 is converted into fraction = 7/10 then
in DENOMINATOR we have 7 *10
Thank you selecting as brainliest
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