the diameter of internal and external surface of a hollow spherical shell are 10 cm and 6 CM if it is melted and recast into a solid cylinder of length
of 2 2/3cm,find the diameter of the cylinder.
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39.58 cm
Step-by-step explanation:
Given,
External diameter of the sphere = 10 cm
Internal diameter of the sphere = 6 cm
Volume of the sphere = (4/3)πr³
= {(4/3) x π x 10³} - {(4/3) x π x 6³} cm³
= (4/3π) (1000 - 216) cm³
= 1,045.33π cm³
Height of the solid cylinder = 2(2/3) = 8/3 cm
Volume of the cylinder = πr²h
⇒ 1,045.33π = π x r² x (8/3)
⇒ r² = (1,045.33 x 3)/8 cm²
⇒ r² = 391.99 cm²
⇒ r = 19.79 cm
The diameter is 39.58 cm.
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