The diameter of internal and external surfaces of a hollow
spherical shell are 6 cm and 10 cm respectively. If it is melted
and recast into a solid cylinder of height 2 2/3 find the diameter of the cylinder
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Answer:
14cm
Step-by-step explanation:
internal diameter of hollow spherical shell- 6cm
internal radius of hollow spherical shell- 6/2 = 3 cm
external diameter of hollow spherical shell - 10cm
internal diameter of hollow spherical shell- 10/2 = 5cm
Let diameter of cylinder be - X cm
Radius of cylinder = X/2 cm
Height of Cylinder = 8/3 cm
ATQ :- volume of cylinder= volume of spherical shell
π ( x/2)² (8/3) = 4/3π (5³-3³)
= 8πx²/ 12 = 4/3π (98)
= 2/3 x² = 4/3 (98)
= x²= 49
x= 7 cm
Radius = 7cm
Diameter= 14 cm
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