The diameter of metallic ball is 35 cm. What is the mass of the ball if the density of metal is 8.9 gm per centimeter cube?
Answers
Question :--- The diameter of metallic ball is 35 cm. What is the mass of the ball if the density of metal is 8.9 gm per centimeter cube ?
Formula used :--
→ Volume of Sphere = 4/3 * π * (r)³ ( where r is radius of sphere , that is Half of diameter ).
→ Mass of the ball = Density of metal * Volume.
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Solution :--
Diameter of sphere is given = 35cm.
So,
→ Radius of sphere = (35/2) cm.
Putting value of radius in Volume formula now,
→ Volume of Sphere = 4/3 * π * (r)³
→ Volume = 4/3 * π * (35/2) ³
→ Volume = (4/3) * (22/7) * (35/2) * (35/2) * (35/2)
→ Volume = (11 * 35 * 35 * 35) /3*7
→ Volume = (471625/21) cm³ .
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Now, it is given that, Density of Metal is 8.9gm /cm³.
And , now we also have Volume of sphere = (471625/21)cm³ .
So,
→ Mass of ball = Density * Volume .
putting values now,
→ Mass of ball = 8.9 * (471625/21)
→ Mass of ball = 199879.17gm.
Now, we know that, ( As SI unit of mass is kg.)
→ 1000gm = 1kg
→ 1gm = (1/1000)kg .
So,
→ 199,879.17gm = (199,879.17)/1000 = 199.879 kg (Approx)