the diameter of neck and bottom of a bottle are 2 centimetre and 10 centimetre respectively the bottle is completely filled with oil if the cork in the neck is pressed in with a force of 1.2 KGF what forces exerted on the bottom of the bottle
Answers
Answered by
117
Given
Dia of the neck=2cm=0.02m
So area of cross section of the neck=π d²/4
=0.000314m²
Diameter of the bottom is = 10 cm = 0.1 m
So, area of cross-section of the bottom is, A = πd 2 /4 = 0.00785 m 2
Force applied to the cork, f = 1.2 kgf
Let F be the force at the bottom, so,
F/A = f/a
=> F = (f/a)A = (1.2/0.000314)(0.00785) = 30 kgf
Dia of the neck=2cm=0.02m
So area of cross section of the neck=π d²/4
=0.000314m²
Diameter of the bottom is = 10 cm = 0.1 m
So, area of cross-section of the bottom is, A = πd 2 /4 = 0.00785 m 2
Force applied to the cork, f = 1.2 kgf
Let F be the force at the bottom, so,
F/A = f/a
=> F = (f/a)A = (1.2/0.000314)(0.00785) = 30 kgf
Answered by
45
Answer:
Explanation:
A1=2X2=4
A2=10X10=100
F1=1.2Kgf
Therefore F1/F2=A1/A2
=1.2/F2=4/100
1.2X100=4F2
120/4=F2
Therefore F2=30Kgf
Pls comment for doubts
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