The diameter of roller 1.5 m long is 84 cm. If it takes 100 revolutions to level
playground, find the cost of levelling this ground at the rate of 50 paise per square
metre.
Answers
Answered by
6
Answer:
r=
2
1.5
=0.75m
h=84cm=0.84m
∴ Curved surface area=2πrh=2×
7
22
×0.75×0.84=3.96m
2
∴ Area of the ground levelled in 1 revolution=3.96m
2
∴ Area of the ground levelled in 100 revolution=3.96m
2
×100=396m
2
∴ Cost of levelling=Rs.396×
100
50
=Rs.198
Answered by
2
Step-by-step explanation:
Hopefully it will be correct
Attachments:
Similar questions