Math, asked by jagasushmijagasushmi, 1 day ago

the diameter of roller 84cm and its length is 120cm. It takes 500 complete revolution to move once to level a playground.the area of the playground in m2 is

Answers

Answered by mp5142437
0

Answer:

Since it takes 500 complete revolutions to move once over to level a playground, the area of the playground will be equal to 500 times the curved surface area of the roller. Let the radius and height of the cylinder are 'r' and 'h' respectively. Thus, area of the playground = 1584 m².

Answered by TPene
0

Answer: area of playground is 1584 m^2

Step-by-step explanation:

Diameter of a roller d  = 84 cm,

Height of cylinder h =Length of roller = 120cm = 1.2 m

Revolutions by roller=500

Base radius of roller (r)=d/2=42cm =0.42 m

Curved surface area of cylinder=(2πrh )=2×(22/7)×0.42×1.2 =3.168 m2

Area of playground

= (revolutions done by roller) × (Curved surface area of roller)

= 3.168×500

= 1584 m2

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