Math, asked by nileshgujju, 10 months ago

The diameter of roller is 120 cm and its height is 1 m.It takes 500 complete revolution to move once over to level a playground.F ind the area of the playground in m^2.

Answers

Answered by HarishTamil
1

Answer:

Area of playground is 3768 sq. metres.

Step-by-step explanation:

Given :

R = 1.2 m

h = 1 m

n = 500

Sol :

CSA of Cylinder = 2πRh

= 2× 3.14 × 1.2 × 1

= 7.536 m²

Area of playground = n × CSA of Cylinder

= 500 × 7.536

= 3768 m²

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