The diameter of roller is 84cm and its length is 120cm. Find the area of playground levelled by roller in 10 revolutions
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the CSA of a cylinder=2*pi*r*h
here,
2*22/7*42*120=44*6*120=31680
the no.of revolutions taken to level the playground once=500
therefore Ar. of the playground=500*31680=15840000cm^2 /1584 m^2
here,
2*22/7*42*120=44*6*120=31680
the no.of revolutions taken to level the playground once=500
therefore Ar. of the playground=500*31680=15840000cm^2 /1584 m^2
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