The diameter of roller is 84cm and its length is 120cm. Find the area of playground levelled by roller in 10 revolutions
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given diameter[d]=84 cm
so,radius[r]=d/2=84/2=42 cm
length[h]=120 cm
CSA of cylinder=2πrh
=2×22/7×42×120
=2×22×6×120
=31680 sq cm
=3168 sq m
The roller can cover 31680 cm² in 1 revolution
area covered in 10 revolution=10×31680=316800 cm².
so,radius[r]=d/2=84/2=42 cm
length[h]=120 cm
CSA of cylinder=2πrh
=2×22/7×42×120
=2×22×6×120
=31680 sq cm
=3168 sq m
The roller can cover 31680 cm² in 1 revolution
area covered in 10 revolution=10×31680=316800 cm².
Answered by
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the area of the playground = 264*120*10
=316800 sq cm
=3168 sq m
Anonymous:
this is an easy way to do it
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