The diameter Of roller is a 84cm and is length 120cm. it take 500 complete revolution to move ones over to level a playground. find the area of the playground In m
![m2 m2](https://tex.z-dn.net/?f=++m2)
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To find the area of the playground, we just need to find the CSA(curved surface area) and multiply it by 500(revolutions taken),
CSA of a cylinder= 2(pi)×r×l [where r(radius)=00.42m and l(length)= 1.2m]
CSA= 2×(22/7)×0.42×1.2
CSA= 3.167 m^2
Area of playground= 500(CSA)
= 500×3.167
= 1,583.5 m^2
It is the correct answer.
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CSA of a cylinder= 2(pi)×r×l [where r(radius)=00.42m and l(length)= 1.2m]
CSA= 2×(22/7)×0.42×1.2
CSA= 3.167 m^2
Area of playground= 500(CSA)
= 500×3.167
= 1,583.5 m^2
It is the correct answer.
Please mark this answer as the BRAINLIEST!
Will be thankful!
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