Question

The diameter of the base of a cyclinder is 49cm. Its height is 8cm. Find its volume ?

Answer 1

$\mathfrak{\green{\huge{Solution}}}$

Given -:

Diameter of the base of the cylinder = 49cm

Therefore,the radius = 49/2

Radius = 24.5cm

Height of the cylinder = 8cm

We know that,

$volume \: of \: the \: cylinder \: = \pi {r}^{2} h$

$= (22 \div 7) \times 24.5 \times 24.5 \times 8$

$= 15092 \: {cm}^{2}$

Answer 2

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$\underline{\underline{\huge{\textbf{Solution:}}}}$

Given,
Diameter of the base of the Cylinder $d = 49\: cm$

Height of the Cylinder $h = 8\: cm$

Volume of the Cylinder $V = ?$

$\underline{\large{\textsf{Step-1:}}}$
Find the radius of base of Cylinder

Since,
Base of the Cylinder is a circle

We have,
$Diameter = 2 \times Radius$

$\implies Radius = \dfrac{Diameter}{2}$

$\therefore Radius\: of\: Base\: of\: Cylinder, \, r= \dfrac{d}{2}$

Substituting Values

$\implies r = \dfrac{49}{2}$

$\implies r = 24.5\: cm$

.$\underline{\large{\textsf{Step-2:}}}$
Find the Volume of Cylinder

We have,
Volume of the Cylinder $V = \pi r^{2} h$

Substituting Values

$\implies V = \pi \times (24.5)^{2} \times 8$

$\implies V = \frac{22}{7} \times (600.25) \times 8$

$\implies V = 15092\: cm^{3}$

$\therefore$
Volume of the Cylinder with base of diameter 49 cm and height 8 cm is $\underline{15092\: cm^{3}}$

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