Question

The diameter of the base of a metallic cone is 2 cm and height is 10 cm. 900 such cones are melted to form one right circular cylinder whose radius is 10 cm. Find the total surface area of the right circular cylinder so formed. (π = 3.14 ) ​

Answer 1

Question:-

The diameter of the base of a metallic cone is 2cm and height is 10cm. 900 such cones are melted to form one right circular whose radius is 10cm. Find the total surface area of the right circular cylinder so formed. (π = 3.14).

Answer:-

Total surface area of the right circular cylinder is 2512cm²

To find:-

Total surface area of the right circular cylinder

Step-by-step explanation:-

Diameter of the base of metallic cone = 2cm

Its radius = 2/2 = 1cm

Its height = 10cm

Volume of metallic = 1/3πr²h

⇒1/3π×1×1×10

⇒10π/3 cm³

∴Volume of 900 metallic cones = 900×10π/3cm³=3000πcm³

900 cones are melted to form a right circular cylinder

∴Volume of a cylinder = 3000π

For a cylinder, radius $(r_{2})$ = 3000π

and height be $(h_{2})$

⇒Volume of a cylinder = $\pi r^{2}_{1}h_{1}$

⇒3000π = π×10× $10h_{2}$

⇒$h_{1}=30cm$

Total surface area of cylinder = $2\pi r_{2}(r_{1}+h_{1}$)

⇒23.1410(10+30)

⇒6.281040

⇒2512cm²

∴Total surface area of the right circular cylinder is "2512cm²"

Answer 2

Answer:

2512. is your answer

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