The diameter of the base of a right circular cylinder in 4.2 dm and it's height is 1 dm. Find the area of the curved surface in cm2.
Answers
Answer:
Question:-
The diameter of the base of a right circular cylinder is 4.2 dm and it's height is 1 dm.Find the curved surface area in cm².
Given:-
- Diameter of circular cylinder = 4.2 dm
- Height of cylinder = 1 dm
To find:-
- Curved surface area = ?
We know,
Now,
➳ Radius of cylinder = Diameter/2
➳ Radius of cylinder = 4.2/2
➳ Radius of cylinder = 2.1 dm
➳ Radius of cylinder = (2.1 × 10) cm
➳ Radius of cylinder = 21 cm
Now,
➜ Height of cylinder = 1 dm
➜ Height of cylinder = (1 × 10) cm
➜ Height of cylinder = 10 cm
➤ CSA of cylinder = 2πrh
➤ CSA of cylinder =2 × 3.14 × 21 × 10
➤ CSA of cylinder = 1318.8 cm²
Answer:
Given:
The diameter of the base of a right circular cylinder in 4.2 dm and it's height is 1 dm.
Find:
Find the area of the curved surface in cm².
Using formula:
Know terms:
(CSA) = Curved surface are.
(R) = Radius.
(H) = Height.
(dm) = decimeters
Calculations:
[ Radius of cylinder ]
[ Height of cylinder ]
[ CSA of cylinder ]
Therefore, 1318.8 cm² is the CSA of cylinder.