Question

The diameter of the base of a right circular cylinder is 35 m and its height is 21 m.
Find its curved surface area. please step by step

Answer 1

Given :

• Diameter of the right circular cylinder = 35 m
• Height of the cylinder = 21 m

To find :

• Curved surface area of the cylinder.

Solution :

Formula Used :-

${\boxed{\bold{CSA\:of\: cylinder=2\pi\:r\:h}}}$

Where,

• r = Radius
• h = Height

• Diameter = 35 m

• Height = 21 m

Then,

• Radius = diameter/2

→ Radius = (35/2 ) m

$\implies\sf{CSA\:of\: cylinder=2\times\dfrac{22}{7}\times\dfrac{35}{2}\times\:21\:\:m^2}$

$\implies\sf{CSA\:of\: cylinder=22\times\:5\times\:21\:\:m^2}$

$\implies\sf{CSA\:of\: cylinder=2310\:\:m^2}$

Therefore, the curved surface area of the cylinder is 2310 m².

_______________

More information :-

• TSA of cylinder = 2πr(h+r)
• Volume of cylinder = πr²h

Answer 2

$\huge\purple{\underline{\underline{\pink{Ans}\red{wer:-}}}}$

$\sf{Curved \ surface \ area \ is \ 2310 \ m^{2}}$

$\sf\orange{Given:}$

$\sf{For \ right \ circular \ cylinder,}$

$\sf{\implies{Diametre (d)=35 \ m}}$

$\sf{\implies{Height (h)=21 \ m}}$

$\sf\pink{To \ find:}$

$\sf{Curved \ surface \ area.}$

$\sf\green{\underline{\underline{Solution:}}}$

$\sf{Curved \ surface \ area \ of \ cylinder}$

$\sf{=2\pi\times \ r\times \ h}$

$\sf{...formula}$

$\sf{But \ 2r=d}$

$\sf{\implies{C.S.A.=\pi\times \ d\times \ h}}$

$\sf{\implies{C.S.A.=\frac{22}{7}\times35\times21}}$

$\sf{\implies{C.S.A.=22\times5\times21}}$

$\sf{\implies{C.S.A.=2310 \ m^{2}}}$

$\sf\purple{\tt{\therefore{Curved \ surface \ area \ is \ 2310 \ m^{2}}}}$