Question

the diameter of the base of a right circular cylinder is 42 cm and the height is 10 cm find its curved surface area

Answer 1

Given :- diameter = 2r = 42cm.
so, radius = 21 cm.
Hight = 10 cm
curved surface area = 2πrh = 2* 22/7 * 21 * 10=
1320 cm^2.
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Answer 2

if diameter=42cm
Then,r=d/2
=>r=42cm/2
=21cm
height=10cm
curved surface area=
$2\pi \times r \times h$
=
$2 \times (22 \div 7) \times 21cm \times 10cm$
=
$2 \times 22 \times 3 \times 10cm ^{2}$
=1320 sq.cm