Question

The diameter of the base of a right circular cylinder is 7 cm. If its height is 40....then the
volume is:​

Answer 1

Step-by-step explanation:

For a right circular cylinder

radius of the base(r) = 7/2 = 3.5 cm

height (h) = 40 cm

Volume = πr²h

= 22/7 × (7/2)² × 40

= 22/7 × 49/4 × 40

= 22×7×10

= 1540 cm³

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Answer 2

Your Answer :

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DIAMETER of the base = 7 cm

As we know that

Radius is twice the diameter.

so, Radius = diameter/ 2

r = 7/2 = 3.5 cm

Height = 40 cm

here, we have to use a formula

Volume of a right circular cone =

1/3∏r^2h

( it is read as one by three pie r square h )

so ,

To get the volume of the cone substitute there respective values...

so,

1/3 × 22/7 × 3.5 × 3.5 × 40

= 10780 / 21

= 531.333-----cm^3 ( the decimal expansion is repeating)

= 531.3 cm^3 ( approximately)

Therefore,

Volume of a right circular cone is 531.3 cm^3.

Note :

Volume of the cone =

$\frac{1}{3} \pi {r}^{2} h$

Radius is two times the diameter