Question

The diameter of the base of cylinder is 2m and height is 1.8m.It is melted and recost in to a cone of diameter 3m. find the height of the cone .solve and explain
Hint:
(Answer is 0.6 )​

Answer 1

Answer:

•If solid of one shape is converted into solid of another shape then, Total volume of the solid to be converted3 Total volume of the solids into which the given solid is to be converted. SOLUTION: GIVEN: Height of a solid metallic right circular cylinder (h) = 1.8 m Diameter of a solid metallic right circular cylinder (d) = 2m Radius of a solid metallic right circular cylinder (r) = d/2 = 2/2 = 1m Diameter of a circular cone (D) = 3m Radius of a circular cone (R) = D/2 = 3/2 m Let ,H be the height of a circular cone. Volume of Cylinder = Volume of Cone Ir?h = V3 (TTR?H) 12 x 1.8 = V3 (3/2)? x H 1.8 x 3 = 9/4 xH 1.8 x 3 x 4 = 9H H = (1.8 x 3 x 4)/9 = 0.6 x4 = 2.4 m Hence, the height of the cone is 2.4 m.

HOPE THIS WILL HELP YOU..

Answer 2

Answer:

Height = 2.4 m

Step-by-step explanation:

Given:

• Diameter of base of cylinder = 2 m

So, radius = 1 m

• Height of cylinder = 1.8 m
• Diameter of cone = 3 m

So, radius of cone = 3/2 m

To find:

• Height of cone = ?

Solution:

Here a cylinder is melted and recast into a cone.

Volume of cylinder = Volume of cone

➝ πr²h = ⅓ πR²H

Cancelling π on both sides,

➝ r²h = ⅓ R²H

➝ 1² × 1.8 = R²H ÷ 3

$\implies \sf{1.8 = \dfrac{3}{2} \times \dfrac{3}{2} \times \dfrac{1}{3} \times height }$

⇒ 1.8 = (3 × Height) ÷ 4

⇒ 1.8 × 4 = 3 × Height

⇒ 7.2 ÷ 3 = Height

⇒ Height = 2.4 m

∴ Height of cone = 2.4 m