Question

the diameter of the base of right circular cone is 12 cm and volume 376.8 cm3 cube .find its height​

Answer 1

Step-by-step explanation:

Volume of a cylinder =

$\frac{1}{ 3} \pi {r}^{2} h$

Diameter = 12cm => radius = 12/2 = 6 cm

$\frac{1}{3} \times 3.14 \times 6 \times 6 \times h = 376.8 {cm}^{3}$

$= > 3.14 \times 6 \times 2 \times h = 376.8$

$= > 37.68 \times h = 376.8$

$= > h = \frac{376.8}{37.68}$

$= > h = 10cm$

Answer 2

Answer:

The height of the cone is 10cm

Step-by-step explanation:

Given that,

The diameter of a base of right circular cone is $D=12cm$

Hence,the radius of the base of the cone is calculated as follows

$= > R=\frac{D}{2} =\frac{12}{2}=6cm$

Also given that,

The volume of the cone is $V=376.8cm^{3}$

We are required to find the height of the cone and we use the relation of volume of a right circular cone which is mentioned below-

$V=\frac{1}{3} \pi r^{2}h$

Substituting the known parameters in the above equation,we get

$376.8=\frac{1}{3} (3.14)(6)^{2}h= > h=\frac{3\times376.8}{3.14\times36} =10\\= > h=10cm$

Therefore,the height of the cone is found to be 10cm

#SPJ2