Question

The diameter of the base of the cylinder is 28 cm and its height is 8cm. What is its volume?​

Answer 1

Volume of a Cylinder = πr²h

$\frac{22}{7} \times 14 \times 14 \times 8$

NOTE= I TOOK RADIUS AS 14 BECAUSE D=RADIUS'S HALF

22*2*14*8=4928

So, The answer to your question is 4928

Answer 2

Given : The diameter of the base of the cylinder is 28 cm and its height is 8cm .

Exigency To Find : Volume of Cylinder.

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⠀⠀⠀⠀⠀First Finding Radius of Cylinder to find Volume :

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{Radius _{(Cylinder)} \:: \dfrac{Diameter}{2}}\bigg\rgroup$

⠀⠀⠀⠀⠀Here Diameter is 28 cm .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \longmapsto \sf Radius = \dfrac{28}{2}$

$\qquad \longmapsto \sf Radius = \cancel {\dfrac{28}{2}}$

$\qquad \longmapsto \frak{\underline{\purple{\:Radius = 14 cm }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Radius \:of\:Cylinder \: \:is\:\bf{\:\:14cm}}}}$

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⠀⠀⠀⠀⠀Finding Volume of Cylinder :

$\qquad \dag\:\:\bigg\lgroup \sf{Volume _{(Cylinder)} \:: \pi r^2 h}\bigg\rgroup$

⠀⠀⠀⠀⠀Here r is the Radius , h is the Height & $\pi =\dfrac{22}{7}$.

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \longmapsto \sf Volume = \dfrac{22}{7} \times (14)^2 \times 8$

$\qquad \longmapsto \sf Volume = \dfrac{22}{7} \times 196 \times 8$

$\qquad \longmapsto \sf Volume = \dfrac{22}{\cancel {7}} \times \cancel {196}\times 8$

$\qquad \longmapsto \sf Volume = 22 \times 28 \times 8$

$\qquad \longmapsto \sf Volume = 616 \times 8$

$\qquad \longmapsto \frak{\underline{\purple{\:Volume = 4928 cm^2 }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Volume \:of\:Cylinder \: \:is\:\bf{\:\:4928cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\boxed{\begin{array}{cc}\bigstar \:\underline{\textbf{Formulae Related to Cylinder :}}\\\\\sf {\textcircled{\footnotesize\textsf{1}}} \:Area\:of\:Base\:and\:top =\pi r^2 \\\\ \sf {\textcircled{\footnotesize\textsf{2}}} \:\:Curved \: Surface \: Area =2 \pi rh\\\\\sf{\textcircled{\footnotesize\textsf{3}}} \:\:Total \: Surface \: Area = 2 \pi r(h + r)\\ \\{\textcircled{\footnotesize\textsf{4}}} \: \:Volume=\pi r^2h\end{array}}$

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