Math, asked by angel51857336, 4 months ago

) The diameter of the circular base of a garden roller is 22 cm and its length is 40 cm. What is the
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lateral surface area of the roller? How much area will it level in 3 complete revolutions? (2+3=​

Answers

Answered by jaya8580
2

Answer:

8,297.14 sq. cm

Step-by-step explanation:

Diameter of the circular base of garden rolller = 22 cm

Radius = 22/2 = 11 cm

Length = 40cm

L.S.A of the garden roller = 2πrh

= 2× 22/7× 11cm×40cm

= 2765.71 sq. cm

Area will it 3 complete revolution= 2765.71×3

= 8,297.14 sq.cm

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