Question

the diameter of the lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm respectively.if its height is 24 cm .the area of the metal sheet used to make the bucket

Answer 1

Hi friend,

DIAMETER OF UPPER PART = 30

RADIUS OF UPPER PART (R) = D/2 = 30/2 = 15CM.

DIAMETER OF LOWER PART = 10CM

RADIUS OF LOWER PART (r) = D/2 = 10/2 = 5CM

HEIGHT OF THE BUCKET (H) = 24 CM

THEREFORE,

SLANT HEIGHT OF THE BUCKET = ✓ H²+ (R-r)² = (24)² + (15-5)².

= ✓ 576 + 400 = ✓976 = 31.24 CM.

THEREFORE,

AREA OF METAL SHEET USED FOR MAKING THE BUCKET = CSA OF BUCKET+ AREA OF BOTTOM OF THE BUCKET = πL(R+r) + πr².

PUT VALUES AND SOLVE U WILL GET YOUR ANSWER.... :-}

Answer 2

Area of metal used= csa of frustum+ area of lower end
Now, r=5cm
R=15cm n h=24cm
Therefore, l=_/24square+(15-5)square
=26cm
Csa of frustum=pi*20*26
Area of lower end=pi*25
Thus total metal neeeded=pi(520+25) cmsq
Hope it helps u