Question

The diameter of the rod is 10 mm and tensile force applied is 100 N. Length of the rod is 200 mm and the deformation of the rod is 205 mm. Find the stress, and strain in the rod
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Answer 1

Answer:

Given that,

Radius r=10mm

Length l=1.0m

Force F=100kN

Young modulus Y=2.0×10

11

Nm

2

Now, the stress is

Stress =

3.14×10

2

m

2

100×10

3

N

=3.18×10

8

Nm

−2

Now, the elongation is

ΔL=

AY

FL

ΔL=

2.0×10

11

3.18×10

8

×1

ΔL=1.59×10

−3

m

ΔL=1.59mm

Now, the strain is

Strain

=

L

ΔL

=

1.0

1.59×10

−3

=1.59×10

−3

Hence, this is the required solution.