The diameter of the roller 120 cm long is 84 cm. If it takes 500 complete revolutions to level a playground determine the cost of levelling it at the rate of 0.50 paise per square meter
Answers
Answer:
total cost = 1131.43 rupees
Step-by-step explanation:
given
diameter of roller D = 120 cm
so radius of roller R = 120/2 = 60 cm
and length of roller L = 84 cm
so the perimeter of roller can be calculated by formula
perimeter of roller = 2пR = 2×(π)×60= 120π cm
it means that the one round of roller is complete 120π cm distance on ground
given the roller complete 500 round on ground so the distance covered by roller
distance by roller = one round distance × 500
distance = 120π×500 cm
= 60000π cm
now the area cover by roller
= length of roller × 60000π
= 120×60000π
= 7200000π cm²
total area cover by roller in 500 round is 7200000π cm² = 720π m²
= 720×(22/7) = 15840/7 m²
cost of levelling rate of 0.50 paise per square meter so
total cost = 0.50×15840/7 =1131.43 rupees