Question

The diameter of the roller is 112cm and its length is 150cm . Find the area
(in m2
) leveled by it in 500 revolutions.

Answer 1

Hello .
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RADIUS=112/2=56 CM

HEIGHT=150 CM

CURVED SURFACE AREA OF CYLINDER=2*pi*R*H

=2*22/7*56*150

=52800

Answer 2

Just did the same question as part of my Maths practice.

Given: Diameter=112cm
Radius= 112÷2
= 56cm
height= 150cm
CSA of roller:
$2\pi {r} h \\ = 2 \times \frac{22}{7} \times {56} \times 150 \\ = 2\times 22 \times 8 \times 150 \\ = 52,800 cm^{2}$
Area levelled:
$500 \times csa \\ = 500 \times 52800 {cm}^{2} \\ = 26400000 {cm}^{2} \\ ( {1m}^{2} = 10000 {cm}^{2} ) \\ = 2640 {m}^{2}$
The roller levelled 2,640m².