Question

the diameter of the roller is 84cm and it's length is 120cm. it takes 500 revolution to move once over to level a playground. find the area of the playground in square meters. ​

Answer 1

Answer:

The area of the playground is 1584m²

Step-by-step explanation:

Given:

• The diameter of the roller is 84 cm
• The length of the roller (h) is 120 cm
• It takes 500 revolutions to level a playground

To find:

The are of the playground

Now,

Radius of the roller = diameter/2 = 84/2 = 42cm

• The formula to find the Curved Surface Area of the roller

= 2πrh unit sq.

= 2 * 22/7 * 42 * 120

= 2 * 22 * 6 * 120

= 31680 cm²

Now,

• 1 revolution = 1 curved surface area

So,

500 revolutions = 500 * CSA of roller

                           = 500 * 31680

                           = 15840000 cm²

⇒ Converting the unit into m sq.

→ 1m = 100 cm

→ 1m² = 10000 cm²

So,

= 15840000/10000 m² = 1584 m²

Hence,

The area of the playground is 1584 m²

Answer 2

Answer:

✡ Given ✡

⬛ The diameter of the roller is 84cm and it's length is 120cm.

⬛ It takes 500 revolution to move once over to level a playground.

✡ To Find ✡

⬛ The area of the playground in square meters.

✡ Solution ✡

➡ Radius of the roller (r) = $\dfrac{84}{2}$ = 42cm

➡ Length of the roller (h)= 120cm

∴ Area of the playground levelled in taking 1 complete revolution 2πrh.

=> =2×227×42×120=31680cm²

∴ Area of the playground ,

=>31680×500

=>15840000cm²

=> $\dfrac{15840000}{100×100}$m²

=> 1584m²

∴The area of the playground is 1584m².

Step-by-step explanation:

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