The diameter of the two right circular cones are equal if their slant heights are in the ratio 3:4,than what is the ratio of their curved surface area?
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Let the ratio of diameters be 3x:4x
So,the ratio of their radii is 3x/2:2x
Ratio of their slant heights is 3x:4x
CSA of cone = πr(r+l)
πr(r+l)/πR(R+L)
r(r+l)/R(R+L)
3x/2(3x/2+3x)/2x(2x+4x)
3x/2(3x+6x/2)/2x(6x)
3x/2(9x/2) / 2x(6x)
27x^2 / 18x^2
27/18
9/6
3/2
The required ratio is 3:2 ...
So,the ratio of their radii is 3x/2:2x
Ratio of their slant heights is 3x:4x
CSA of cone = πr(r+l)
πr(r+l)/πR(R+L)
r(r+l)/R(R+L)
3x/2(3x/2+3x)/2x(2x+4x)
3x/2(3x+6x/2)/2x(6x)
3x/2(9x/2) / 2x(6x)
27x^2 / 18x^2
27/18
9/6
3/2
The required ratio is 3:2 ...
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