Question

The diameter of the wheel of a car is 35 sem
How much distance will it cover in 100 revolution​

Answer 1

CORRECTED QUESTION

The diameter of the wheel of a car is 35 cm .How much distance will it cover in 100 revolution​ ?

Answer:

$\blue\bigstar$ Distance covered in 100 revolution = 11000 cm.

Solution

Diameter of the wheel of the car = 35cm.

$\boxed{\sf Radius = \dfrac{Diameter }{2} }$

$\sf Radius \: of \: the \: wheel\: of\: the \: car = \dfrac{35}{2}cm.$

⇒ $\sf Radius \: of \: the \: wheel\: of\: the \: car = 17.5cm.$

THE WHEEL

$\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\qbezier(2.3,0)(2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,2.121)(0,2.3)\qbezier(-2.3,0)(-2.121,-2.121)(0,-2.3)\qbezier(2.3,0)(2.121,-2.121)(-0,-2.3)\put(0,0){\line(1,0){2.3}}\put(0.5,0.3){\bf\large 17.5cm}\end{picture}$

$\boxed{\sf Distance \: covered \: in \:one \:revolution \:of \:the \:wheel = Circumference \:of \: the \: wheel}$

$\boxed{\boxed{\boxed{\sf Circumference \: of\: a \:circle = 2\pi r}}}$

⇒ $\sf Circumference \: of \: the\: wheel = 2* \pi * 17.5$

⇒ $\sf Circumference \: of \: the\: wheel = 35 * \pi$

Distance covered in one revolution = 35π.

Distance covered in 100 revolution=Distance covered in one revolution×100

⇒ 35π × 100

⇒ 3500π

Now,

Let us put , π = 22/7

$\implies \sf Distance \: covered\: in\: 100 \:revolution = 3500 * \dfrac{22}{7}$

$\implies \sf Distance \: covered\: in\: 100 \:revolution = \dfrac{77000}{7}$

$\implies \sf Distance \: covered\: in\: 100 \:revolution = 11000 cm.$

$\implies \sf$ Distance covered in 100 revolution = 11000 cm = 110m.