The diameter of two circles are 36 cm and 20 cm respective -- Piese area of the c
which has circumference equal to the sum of the circunferences of the two circles.
find ratio of area of this big circle and the sum of area of two s nalí eszcie.
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Answered by
24
HI FRIEND
GOOD QUESTION
Answer. cm=10 cm. =(36+20)π cm=56π cm. This is the circumference C of the resulting circle
Answered by
44
Area = 2464 cm²
Ratio = 98 : 53
Let the radius of the required circle be 'R'.
Radius of 1st circle = d/2 = 36/2 = 18 cm
Radius of 2nd circle = 20/2 = 10 cm
As given, circumference of biggest circle = circumference of 1st circle + circumference of 2nd circle.
=> 2π(18) + 2π(10) = 2πR
=> 2π[18 + 10] = 2πR
=> 18 + 10 = R
=> 28 = R
Area of biggest circle= πR² = π(28)² = π(784) = 2464 cm²
Sum of area of 1st + 2nd circle = π(18)² + π(10)² = π(18² + 10²) = π(424)
Required ratio = π(784)/ π(424)
Required ratio = 784/424 = 98/53
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