Question

The diameter of two circles are 36 cm and 20 cm respective Piese area of the .which has circumference equal to the sum of the circunferences of the two circles.find ratio of area of this big circle and the sum of area of two snail is 10.​

Answer 1

Answer:

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Answer 2

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• Area = π(784) = 352 cm²

• Ratio = 98 : 53

Step - by - step explanation :

Let the radius of the required circle be 'R'.

Radius of 1st circle = d/2 = 36/2 = 18 cm

Radius of 2nd circle = 20/2 = 10 cm

As given, circumference of biggest circle = circumference of 1st circle + circumference of 2nd circle.

⇒ 2π(18) + 2π(10) = 2πR

⇒ 2π[18 + 10] = 2πR

⇒ 18 + 10 = R

⇒ 28 = R

Area of biggest circle= πR² = π(28)² = π(784) = 352 cm²

⛬ Area = π(784) = 352 cm².

Sum of area of 1st + 2nd circle = π(18)² + π(10)² = π(18² + 10²) = π(424)

Required ratio = π(784)/ π(424)

Required ratio = 784/424 = 98/53

⛬ Ratio = 98 : 53.