the diameter of two circles are 8 cm and 12 cm respectively.find the ratio of the area of the smaller circle to that of the larger
Answers
Answered by
5
Answer:
4:9
Step-by-step explanation:
Let d1=8cm, d2=12cm
r1=d1/2=8/2=4 cm
r2=d2/2=12/2=6 cm
Area of circle 1 = π*r1²=π×4×4
Area of circle 2=π*r2²=π×6×6
Ratio=π×16/π×36=16/36=4/9=4:9
Answered by
4
Answer:
4:9
Step-by-step explanation:
☆Let diameters of two circles are 2r and 2R.
Therefore, radii of two circles are r and R.
▪2r = 8 cm
r = 4 cm
▪2R = 12 cm
R = 6 cm
☆Let area of smaller circle is a and that of larger circle is A.
▪a = pi x r^2
a = pi x 4 x 4
a = pi x 16
a = 16 pi cm^2
▪A = pi x R^2
A = pi x 6 x 6
A = pi x 36
A = 36 pi cm^2
☆ATQ:
▪a : A = 16 pi cm^2 : 36 pi cm^2
a : A = 16 : 36
a : A = 4 : 9
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