The diameter of two silver discs are in the ratio 2:3.what will be the ratio of their areas solution.
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Answered by
12
Heya
Let the radii of the two silver dics be r1 and r2 respectively.
Given :-
Ratio of diameters = 2 : 3
Now,
Ratio of radii = Ratio of diameters = 2 : 3
Therefore, r1 / r2 = 2 / 3
Now,
Area of 1st circle = π r1²
Area of 2nd circle = π r2²
Ratio :-
= π r1² / π r2²
= r1²/r2²
= (r1 / r2)²
= (2 / 3)²
= 4/9
Hence, ratios of their areas = 4 : 9.
Hope this helps.
Let the radii of the two silver dics be r1 and r2 respectively.
Given :-
Ratio of diameters = 2 : 3
Now,
Ratio of radii = Ratio of diameters = 2 : 3
Therefore, r1 / r2 = 2 / 3
Now,
Area of 1st circle = π r1²
Area of 2nd circle = π r2²
Ratio :-
= π r1² / π r2²
= r1²/r2²
= (r1 / r2)²
= (2 / 3)²
= 4/9
Hence, ratios of their areas = 4 : 9.
Hope this helps.
Answered by
2
let the radii of the two silver dics be r1 and r2 respectively.
Given :-
Ratio of diameters = 2 : 3
Now,
Ratio of radii = Ratio of diameters = 2 : 3
Therefore, r1 / r2 = 2 / 3
Now,
Area of 1st circle = π r1²
Area of 2nd circle = π r2²
Ratio :-
= π r1² / π r2²
= r1²/r2²
= (r1 / r2)²
= (2 / 3)²
= 4/9
Hence, ratios of their areas = 4 : 9.
hitesh200707:
thanks
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