the diameter of wheel of a car is 77cm . how many revolution will it make to travel 121km
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Diameter of the wheel = 77 cm = 77 / 100000 Km = 0.00077 km.
So the circumference of the wheel = 2 x 22/7 x r = 22/7D = 22/7 x 0.00077 = 0.00242 Mts.
The distance travelled by car = 121 Kms.
So the number of revolution the wheel will take to travel 121 Km = 121 / Circumference of the wheel
= 121/0.00242 = 50000 nos.
Ans: 50000 Nos.
So the circumference of the wheel = 2 x 22/7 x r = 22/7D = 22/7 x 0.00077 = 0.00242 Mts.
The distance travelled by car = 121 Kms.
So the number of revolution the wheel will take to travel 121 Km = 121 / Circumference of the wheel
= 121/0.00242 = 50000 nos.
Ans: 50000 Nos.
pinkysingh3949owm8x5:
But in book it is given 15,000 km
Answered by
5
Given the diameter of the wheel = 77cm.
Then the radius will be r = d/2 = 77/2.
We know that circumference of the wheel = 2pir
= 2 * 22/7 * 77/2
= 242 cm.
We know that 1cm = 1/100 m
242 cm = 242/100 = 2.42m.
Given that distance covered = 121 km.
= 121000 m.
The total number of revolutions of the wheel = 121000/2.42
= 50000.
The number of revolutions traveled = 50000.
Hope this helps!
Then the radius will be r = d/2 = 77/2.
We know that circumference of the wheel = 2pir
= 2 * 22/7 * 77/2
= 242 cm.
We know that 1cm = 1/100 m
242 cm = 242/100 = 2.42m.
Given that distance covered = 121 km.
= 121000 m.
The total number of revolutions of the wheel = 121000/2.42
= 50000.
The number of revolutions traveled = 50000.
Hope this helps!
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