The diameter ofa roller is 70 cm and its length is 120cm. It takes 500 complete revolutions to move once over a level a playground. Find the area of the playground in m2.
Answers
Answer:
Radius of the roller (r)=
2
84
cm=42cm
length of the roller (h)=120cm
∴ Area of the playground levelled in taking 1 complete revolution 2πrh
=2×227×42×120=31680cm
2
∴ Area of the playground
=31680×500=15840000cm
2
100×100
15840000
m
2
=1584m
2
Step-by-step explanation:
Radius of the roller (r)=
2
84
cm=42cm
length of the roller (h)=120cm
∴ Area of the playground levelled in taking 1 complete revolution 2πrh
=2×227×42×120=31680cm
2
∴ Area of the playground
=31680×500=15840000cm
2
100×100
15840000
m
2
=1584m
2
Radius of roller : 70/2
= 35 cm
Length of roller : 120 cm
Area of the playground levelled in taking 1 complete revolution 2πrh
2×227×35×120=1906800cm square
Area of the playground : 1906800*500=953,400,000 cm square
Now , change this in M square for doing that
953,400,000 /100*100=
953,400,000/10,000=95,340 m square is answer
Hence final answer is 953,340 m square