the diameter two silver discs are in ratio of 2 :3 what will be the ratio of there areas
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let the common factor be x...so
2:3 =>2x/3x....so the diameter of the first silver disc =2x and of the 2nd disc = 3x..so radius= 2x/2=x cm and of the 2nd disc =3x/2 cm..so ratio of the areas of the two silver disc =π *x^2 : π * (3x/2)^2 => 4:9
2:3 =>2x/3x....so the diameter of the first silver disc =2x and of the 2nd disc = 3x..so radius= 2x/2=x cm and of the 2nd disc =3x/2 cm..so ratio of the areas of the two silver disc =π *x^2 : π * (3x/2)^2 => 4:9
sunil9:
4:9 if d1:d2= 2:3 then r1:r2=2:3 so,area = 4:9
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