Question

The diameters of a circles 4cm and 6cm respevtively find the ratio of their areas

Answer 1

$\large\underline{\underline{\sf Given:}}$

• Diameter of first circle = 4cm

•°• Radius of first circle is $\sf{r_1}$= 2cm

• Diameter of second circle = 6cm

•°• Radius of second circle $\sf{r_2}$= 3cm

$\large\underline{\underline{\sf To\:Find:}}$

• Ratio of their area $\sf{\frac{A_1}{A_2}}$= ?

$\large\underline{\underline{\sf Solution:}}$

$\large{\boxed{\sf Area\:of\:Circle=πr^2 }}$

•°•

$\large\implies{\sf \dfrac{A_1}{A_2}=\dfrac{πr_1^2}{πr_2^2} }$

$\large\implies{\sf \dfrac{A_1}{A_2}=\left(\dfrac{2}{3}\right)^2}$

$\large\implies{\sf \dfrac{A_1}{A_2}=\dfrac{4}{9}}$

$\Large\underline{\underline{\sf Answer:}}$

•°• Ratio of $\sf{A_1\:and\:A_2}$ is 4:9