Question

The diameters of the internal and external surface of a hollow hemispherical shell are 6 cm and 10 cm respectively. If it is melted and recast into a solid cylinder of diameter 14 cm, find the height of the cylinder

Answer 1

check the answer if right then u can refer this

Answer 2

Answer:

The  Height  of the cylinder is 8/3 cm.

Step-by-step explanation:

Given :  

Internal diameter of a hollow spherical shell =6 cm

Internal radius of a hollow spherical shell ,r = 3 cm

External diameter of a hollow spherical shell = 10 cm

External radius of a hollow spherical shell ,R = 5 cm

Diameter of a cylinder = 14 cm

Radius of the cylinder, r1 = 14/2 = 7 cm

Volume of the hollow spherical shell = 4/3π(R³ − r³)

Volume of the solid cylinder = πr1²×h

Since, the hollow spherical shell is melted and recast into a solid  cylinder , so volume of both are equal

Volume of the hollow spherical shell  = Volume of the solid cylinder

4/3π(R³ − r³) = πr²×h

4/3π(5³ - 3³) = π(7)² × h

4/3 (125 - 27) = 49 h

4/3 × 98  = 49 h

h = (4/3 × 98)/49

h = (4 × 98)/ 3 × 49

h = 8/3

Height  of the cylinder = 8/3  cm

Hence, the  Height  of the cylinder is 8/3 cm.

HOPE THIS ANSWER WILL HELP YOU...