Math, asked by goswamikushal3p3zr4d, 1 year ago

The diameters of the lower and upper ends of a bucket in the form of a frustu. of cone are 10cm and 30cm respectively.if its height is 24cm find the area of the metal sheet use to make the bucket

Answers

Answered by nitthesh7
3
Area of metal sheet to be used = CSA of Frustum + Area of base

                                                  = πl(R+r) + πr²

l = √h² + (R-r)²

l = √(24)² + (15-5)²

l = √576 + 100

l = √676 = 26 cm


Then,                                         = πl(R+r) + πr²

                                                  = 3.14 × 26 (15+5) + 3.14 (5)²

                                                  = 3.14 (26 × 20 + 25)  

                                                  = 3.14 (520 + 25)

                                                  = 3.14 × 525

                                                   = 1711.3cm²

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Answered by topanswers
0

Given:

Diameter of the upper end = 30 cm

Diameter of the lower end = 10 cm

Height = 24 cm

To find:

Area

Solution:

Radius of the upper end of the cone = 15 cm

Radius of the lower end of the cone = 5 cm

In order to find the area,

The slant height should be calculated.

Slant height = √ ( h^2 + ( Radius of the upper end of the cone - Radius of the lower end of the cone )^2

√24^2 + ( 15 - 5 )^2  

√576 + 10^2

Slant height = 26 cm

Area of the metal  = Curved surface Area + Area of base of the cone.

Curved surface area = π ( Radius of the upper end of the cone - Radius of the lower end of the cone ) * Slant height

Area of the base = πr2^2

Hence,

π ( Radius of the upper end of the cone - Radius of the lower end of the cone ) * Slant height +  πr2^2

3.14 ( 15 + 5 ) × 26 + π( 5 )^2  

3.14 × 20 × 26 + 25 × 3.14

545 × 3.14

Area = 1711.3 sq.cm

Hence, the area of metal sheet used to make the bucket is 1711.3 sq.cm

Read more on Brainly.in - https://brainly.in/question/3116353

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