the diameters of the lower and upper ends of a bucket in the form of a frustum of a cone are 10 cm and 30 cm respectively.If its height is 24 cm then find the area of the metal sheet used to make the bucket
Answers
GIVEN :
Diameter of upper end of bucket =30cm
Radius of the upper end of the frustum of cone( r1) = 15cm
Diameter of lower end of bucket = 10 cm
radius of the lower end of the frustum of cone( r2) = 5 cm
Height of the frustum of Cone ,h = 24 cm
Slant height of bucket ( L)= √(h² + (r1- r2)²
L =√24² + (15 - 5)² = √576 + 10²
L =√(576+(100)= √676 = 26 cm
L = 26 cm
Area of metal sheet require to make it = π(r1 + r2)L + πr2²
= 3.14(15 + 5) × 26 + π(5)²
= 3.14 × 20 × 26 + 25 × 3.14
= 3.14 (520+ 25)
= 545 × 3.14
Area of metal sheet require to make it = 1711.3 cm²
Hence, the Area of metal sheet used to make the bucket is 1711.3 cm².
HOPE THIS WILL HELP YOU....
Given:
Diameter of the upper end = 30 cm
Diameter of the lower end = 10 cm
Height = 24 cm
To find:
Area
Solution:
Radius of the upper end of the cone = 15 cm
Radius of the lower end of the cone = 5 cm
In order to find the area,
The slant height should be calculated.
Slant height = √ ( h^2 + ( Radius of the upper end of the cone - Radius of the lower end of the cone )^2
√24^2 + ( 15 - 5 )^2
√576 + 10^2
Slant height = 26 cm
Area of the metal = Curved surface Area + Area of base of the cone.
Curved surface area = π ( Radius of the upper end of the cone - Radius of the lower end of the cone ) * Slant height
Area of the base = πr2^2
Hence,
π ( Radius of the upper end of the cone - Radius of the lower end of the cone ) * Slant height + πr2^2
3.14 ( 15 + 5 ) × 26 + π( 5 )^2
3.14 × 20 × 26 + 25 × 3.14
545 × 3.14
Area = 1711.3 sq.cm
Hence, the area of metal sheet used to make the bucket is 1711.3 sq.cm
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