Question

the diameters of the lower and upper ends of the bucket in the form of a frustum of cone are 10 cm and 30cm if its height is 24 cm then find its volume?

Answer 1

GIVEN :Diameter of upper end of bucket =30cm
Radius of the upper end of the frustum of cone( R) = 15cm
Diameter of lower end of bucket = 10 cm
radius of the lower end of the frustum of cone( r) = 5 cm
H of the frustum of Cone = 24 cm
Volume of bucket = 1/3πh[R² + r² + Rr]
= 1/3×3.14×24[15² + 5² + 15×5]   [π= 3.14]
= 25.12[225 + 25+ 75]
= 25.12 × 325 =8164 cm³
Volume of bucket = 8164 cm³
Hence, the volume of the bucket is 8164 cm³.

HOPE THIS WILL HELP YOU...

Answer 2

Answer:

8171.4 cm^3

Step-by-step explanation:

Since we know diameter is twice the radius or D = 2 r or r = D / 2

First we will find the radius for the lower and upper ends of the bucket.

Diameter of lower end of the bucket = 10 cm. So r = 10 / 2 = 5 cm

Diameter of upper end of the bucket = 30 cm. So R = 30 / 2 = 15 cm

Given height is 24 cm.

Volume of a cone is given by the formula

 V = 1/3 π h (R^2 + r^2 + R r)

V = 1/3 x 22/7 x 24 (225 + 25 + 75)

V = 1/3 x 22/7 x 24(325)

V = 176/7 x 325

V = 8171.4 cm^3

So volume of the frustum of cone is 8171.4 cm^3