the diameters of the lower and upper ends of the bucket in the form of a frustum of a cone are 10 cm and 30 cm . if the height is 24 cm find the area of the metal sheet to make the bucket
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Let r1=30/2= 15 cm
and r2 = 10/2 = 5 cm
Given h=24 cm
Slant height, l =
root [h^2 + (r1-r2)^2]
=root (24^2 + 10^2)
=26 cm
Area of metal sheet required
= CSA of frustum + Base area
= pie l (r1+r2) + pie r2^2
= 22/7 × 26 × (15+5) + [22/7 ×25]
= 22/7 [ 520 + 25]
= 22/7 (545)
=1712.85 cm Sq.
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