The diameters of the pistons in a hydraulic machine are 2 cm and 20 cm. If a force of 25 kgf is applied on the smaller piston, calculate the force exerted on the bigger piston. Neglect friction.
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Answer:
∴ Force on Larger= Area of smaller/Force on smaller
×Area of larger
⇒
2.5×2.5×3.14/50
×12.5×12.5×3.1
=1250kgf
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Hey, this is your answer
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