The diameters of the two pistons of a hydraulic machine are 5 cm and 30 cm. Find the force exerted on the larger piston if a force of 60 kgf is applied on the smaller one.
Answers
Answered by
0
Answer:
force is 10N
Explanation:
It is easy!
Formula is F1/A1=F2/A2
F1/5=60/30
Solve for F1
F1= 10N
Similar questions