Question

the diameters of three circles are in the ratio 3:5:6. If the sum of the circumferences of these circles are 308 cm find the difference between the areas of the largest and the smallest of these circles​

Answer 1

Let the diameters of three circles be X.

Then,According to the question

3x + 5x + 6x = 308

14x = 308

X = 308 ÷ 14

X = 22

3x = 3×22=66

5x=5×22=110

6x=6×22=132

largest and smallest Diameter of these circles= 132,66

πr square

22/7 × 132

= 3.14 × 132

= 414.48

22/7 × 66

= 3.14 × 66

= 207.24

Difference = 414.48 - 207.24

= 207.24

If my answer give success to you, then you please mark me as brainlist and follow me.

Answer 2

Step-by-step explanation:

let let the diameter of of each circle be 3x 5x 6x

a/q

22/7(3x+5x+6x)=308

22/7*14x=308

308/7x=308

308x=308*7

x=308*7/308

x=7

diameter of each circle

3x=21cm

5x=35cm

6x=42cm

radius of first and last circle is

10.5 and 21

area =22/7*10.5*10.5

=22*1.5*10.5

=346.5cm^2

area of big circle=22*7*21*21

=22*3*21

=1386cm^2

difference=1386-346.5

=1039.5cm^2