The diameters of three concentric regions of an archery target are in the ratio of 1:2:3. Find the ratio of the area of each region.
(Steps to be shown please)
(Please answer it fast as it is very urgent!!!)
Answers
Answered by
2
since diameters are in ratio1:2:3
then radii also in ratio 1:2:3
let r be the radius of 1st centre circle is
and then radius of 2nd is 2r and 3rd is 3r
therefore area of 1st=Πr^2
2nd = Π(4r^2)
3rd=Π(9Πr^2)
hence areas ratio is 1:4:9
then radii also in ratio 1:2:3
let r be the radius of 1st centre circle is
and then radius of 2nd is 2r and 3rd is 3r
therefore area of 1st=Πr^2
2nd = Π(4r^2)
3rd=Π(9Πr^2)
hence areas ratio is 1:4:9
Faiqa93:
Thnx a lot!!!
welcome
Similar questions