the diameters of two circle with Centre A and B are 16 cm and 30 cm respectively if area of circle with Centre C is equal to the difference of areas of the other two circle then find the circumference of the circle with Centre c
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r of circle A = 8 cm
r of circle B = 15 cm
area of circle C = B-A
=( π*15*15)-(π*8*8)
=π(225-64)
=π(161)
=161π
so, πR*R= 161π , where R is the radius of C
R*R= 161
R. = √161 = 12.69(approx.)
thus, circumference=2π12.69=80cm(approx.)
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r of circle B = 15 cm
area of circle C = B-A
=( π*15*15)-(π*8*8)
=π(225-64)
=π(161)
=161π
so, πR*R= 161π , where R is the radius of C
R*R= 161
R. = √161 = 12.69(approx.)
thus, circumference=2π12.69=80cm(approx.)
plz mark as brainliest
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