The diameters of two circles with centre A and B are 16cm and 30cm respectively. If the area of a circle with centre C is equal to the difference of areas of other two circles, then find the circumference of the circle with centre C.
Answers
Answered by
41
d1 = 16cm, d2 = 30cm
therefore r1 = 8cm, r2 = 15 cm
area C = area B - area A
= πr2² - πr1²
= π ( 15² - 8² )
= π ( 225 - 64 )
= 22/7 * 161
= 22 * 23 cm²
= 506 cm²
therefore,
πr² = 506
22/7 * r² = 506
r² = 506 * 7/22 = 23 * 7
r = √161
circumference = 2πr
= 2 * 22/7 * √161
= 79.76 cm
therefore circumference of circle C is 79.76 cm.
therefore r1 = 8cm, r2 = 15 cm
area C = area B - area A
= πr2² - πr1²
= π ( 15² - 8² )
= π ( 225 - 64 )
= 22/7 * 161
= 22 * 23 cm²
= 506 cm²
therefore,
πr² = 506
22/7 * r² = 506
r² = 506 * 7/22 = 23 * 7
r = √161
circumference = 2πr
= 2 * 22/7 * √161
= 79.76 cm
therefore circumference of circle C is 79.76 cm.
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Answered by
10
is it correct??
May this will help you
May this will help you
Attachments:
thoda dimak aur lagaeye
√161 kisi ka root nahi hota
√169 13 ka square hota hai
161 is not 13²
yahi to mai bhi bol raha hu
ok ji..... dimak lag gaya
my mistake
all right
kk
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