The diameters of two silver discs are in the ratio 2:3.What will be the ratio of their areas. (Class-7th)
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radius will also be in the ratio 2:3.Let r=2x and R=3x. then area of smaller one will be 22/7×2x×2x=88x×x÷7. Similarly find the area of second circle and then divide both areas. You will set the ratio 2:3
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Given,
Ratio of the diameters = 2:3
Let the diameters be 2x and 3x
So, radii of the discs = 2x/2 and 3x/2
= x and 3x/2
Ratio of the area of the discs = πx² / π(3x/2)²
= πx² / π(3x/2)²
= 4x² / 9x²
= 4 / 9
= 4 : 9
Therefore, The ratio of the areas of two silver discs will be 4 : 9.
Ratio of the diameters = 2:3
Let the diameters be 2x and 3x
So, radii of the discs = 2x/2 and 3x/2
= x and 3x/2
Ratio of the area of the discs = πx² / π(3x/2)²
= πx² / π(3x/2)²
= 4x² / 9x²
= 4 / 9
= 4 : 9
Therefore, The ratio of the areas of two silver discs will be 4 : 9.
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