Question

The diameters of two silver discs are in the ratio 2:3. What will be the ratio of their areas?

Answer 1

Answer:

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Answer 2

4:9 ,I think

Step-by-step explanation:

let , diameter of first disc is 2x and second one's is 3x (due to 2x:3x)

now their area be

area of circle =

$\pi {r}^{2}$

area of first disc =

$\pi {( \frac{2x}{2} )}^{2} = \frac{4 {x}^{2}\pi }{4} = {x}^{2} \pi$

area of second disc =

$\pi { \frac{3x}{2} }^{2} = \frac{9 {x}^{2} \pi}{4}$

ratio of first and second disc's areas =

$\frac{ {x}^{2}\pi }{ \frac{9 {x}^{2} \pi}{4} } = \frac{4 \times {x\pi}^{2} }{9 {x}^{2}\pi } = \frac{4}{9}$

or 4:9

hope helps.

if correct please mark brainliest