the dice are thrown simultanosly the probability of getting a sum of 9 is
Answers
Answered by
0
Answer:
Explanation: In two throws of a die, n(S) = (6 x 6) = 36. Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}. P(E) =n(E)/n(S)=4/36=1/9.
Answered by
0
1/9
thiis is your answer
Similar questions